Joint Probability Calculator

Probability

Joint Probability Calculator

Calculate P(A ∩ B), P(A ∪ B), and conditional probabilities for independent and dependent events.

Input Parameters

Results

P(A ∩ B) — Both events occur
0.150000
P(A ∪ B) — At least one occurs
0.650000
P(not A)
0.700000
P(not B)
0.500000

What is Joint Probability?

Joint probability is the probability that two or more events occur simultaneously. Denoted P(A ∩ B), it answers: "What's the chance both A and B happen?"

For independent events: P(A ∩ B) = P(A) × P(B)

Key Concepts:

  • Independent events: One event's outcome doesn't affect the other. Multiply probabilities directly.
  • Dependent events: One event affects the other. Use P(A ∩ B) = P(A) × P(B|A), where P(B|A) is the conditional probability.
  • Union (P(A ∪ B)): Probability of at least one event occurring. Formula: P(A ∪ B) = P(A) + P(B) − P(A ∩ B).
  • Complement: P(not A) = 1 − P(A). Useful for finding probabilities of negations.

Real-world examples:

  • Drawing two cards without replacement (dependent)
  • Flipping two coins (independent)
  • Weather on consecutive days (dependent)
  • Two students independently choosing workshop times (independent)

How to Calculate Joint Probability

For Independent Events:

1

Identify that the events are independent (one doesn't affect the other).

2

Multiply: P(A ∩ B) = P(A) × P(B)

For Dependent Events:

1

Calculate P(A ∩ B) = P(A) × P(B|A), where P(B|A) depends on A occurring.

2

Use Bayes' theorem if needed: P(B|A) = P(A ∩ B) / P(A)

For Union (At Least One):

1

Use: P(A ∪ B) = P(A) + P(B) − P(A ∩ B). Subtract the intersection to avoid counting it twice.

Example Calculations

Independent Events: Two Fair Dice

P(First die = 3) = 1/6 ≈ 0.167 P(Second die = 5) = 1/6 ≈ 0.167 P(First=3 AND Second=5) = 1/6 × 1/6 = 1/36 ≈ 0.0278 Both dice rolls are independent—the first doesn't affect the second.

Dependent Events: Drawing Cards Without Replacement

P(1st card is Ace) = 4/52 ≈ 0.077 P(2nd card is Ace | 1st was Ace) = 3/51 ≈ 0.059 P(Both Aces) = (4/52) × (3/51) ≈ 0.00452 The second draw depends on the first—fewer cards and aces remain.

Union: At Least One Event

P(A) = 0.3, P(B) = 0.5 (independent) P(A ∩ B) = 0.3 × 0.5 = 0.15 P(A ∪ B) = 0.3 + 0.5 − 0.15 = 0.65 There's a 65% chance at least one event occurs.

Frequently Asked Questions

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